# Section-1: Complex Arrangement Solved QuestionLogical Reasoning Discussion

Common Information

There are five sets of digits - Set A, Set B, Set C, Set D and Set E as shown in given diagram. Set A contains one digit, Set B contains two digits, Set C contains three digits, Set D contains two digits and Set E contains one digit. Rearrange the digits, across the sets such that the number formed out of digits of Set C is multiple of the numbers formed from digits in the sets on either side. For example; in the given diagram, Set C is multiple of digits in Set A and Set B but not of Set D and Set E.

Table below can be scrolled horizontally

SET A SET B SET C SET D SET E
7 28 196 34 5
 Q. Common Information Question: 1/2 What is the minimum number of rearrangements required to arrive at the solution? A rearrangement is defined as an exchange of positions between digits across two sets. For example: when 1 from set C is exchanged with 5 of set E, it is counted as one rearrangement.
 ✖ A. 2 ✔ B. 3 ✖ C. 5 ✖ D. 7 ✖ E. 8

Solution:
Option(B) is correct

We have,

Table below can be scrolled horizontally

SET A SET B SET C SET D SET E
7 28 196 34 5

Now in the first rearrangement, 7 from set A is exchanged with 2 of set B to get the following:

Table below can be scrolled horizontally

SET A SET B SET C SET D SET E
2 78 196 34 5

Now in the second rearrangement, 4 from set D is exchanged with 5 of set E to get the following:

Table below can be scrolled horizontally

SET A SET B SET C SET D SET E
2 78 196 35 5

Now in the third rearrangement, 9 from set C is exchanged with 5 of set D to get the following:

Table below can be scrolled horizontally

SET A SET B SET C SET D SET E
2 78 156 39 4

Thus, a minimum of 3 rearrangements is required.

Hence, option B is the correct choice.

## (1) Comment(s)

Akki
()

Shouldn't the ans be 2 ie minimum 2 rearrangements are required

1 st exchange 8 and 7 between set a and set b and in 2nd rearrangement exchange 5 and 4 between set d and set e