Logical Reasoning Discussion

**Common Information**

There are five sets of digits - Set A, Set B, Set C, Set D and Set E as shown in given diagram. Set A contains one digit, Set B contains two digits, Set C contains three digits, Set D contains two digits and Set E contains one digit. Rearrange the digits, across the sets such that the number formed out of digits of Set C is multiple of the numbers formed from digits in the sets on either side. For example; in the given diagram, Set C is multiple of digits in Set A and Set B but not of Set D and Set E.

Table below can be scrolled horizontally

SET A | SET B | SET C | SET D | SET E |
---|---|---|---|---|

7 | 28 | 196 | 34 | 5 |

Q. |
Which of the following pair of digits would occupy set A and E? |

✔ A. |
2 and 4 |

✖ B. |
2 and 6 |

✖ C. |
3 and 6 |

✖ D. |
3 and 9 |

✖ E. |
4 and 8 |

**Solution:**

Option(**A**) is correct

We have,

Table below can be scrolled horizontally

SET A | SET B | SET C | SET D | SET E |
---|---|---|---|---|

7 | 28 | 196 | 34 | 5 |

Now in the first rearrangement, 7 from set A is exchanged with 2 of set B to get the following:

Table below can be scrolled horizontally

SET A | SET B | SET C | SET D | SET E |
---|---|---|---|---|

2 | 78 | 196 | 34 | 5 |

Now in the second rearrangement, 4 from set D is exchanged with 5 of set E to get the following:

Table below can be scrolled horizontally

SET A | SET B | SET C | SET D | SET E |
---|---|---|---|---|

2 | 78 | 196 | 35 | 5 |

Now in the third rearrangement, 9 from set C is exchanged with 5 of set D to get the following:

Table below can be scrolled horizontally

SET A | SET B | SET C | SET D | SET E |
---|---|---|---|---|

2 | 78 | 156 | 39 | 4 |

From the above analysis, we get that set A and set E contains 2 and 4.

Hence, **option A** is the correct choice.