Aptitude Discussion

Q. |
A number when divided by 342 gives a remainder 47. When the same number is |

✖ A. |
5 |

✔ B. |
9 |

✖ C. |
4 |

✖ D. |
0 |

**Solution:**

Option(**B**) is correct

On dividing the given number by 342, let $k$ be the quotient and 47 as remainder.

Then,

$\text{number} - 342k + 47 = (19 × 18k + 19 × 2 + 9)$

$= 19 (18k + 2) + 9$

⇒ The given number when divided by 19, gives $18k + 2$ as quotient and **9** as remainder.

**Saikat Chakraborty**

*()
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**Shobia**

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multiplay 342 by 2-> 684+47=731

i.e) 731/342 will give remainder 47

then.., 731/19 will give remainder 9

ans:9

$N=342a+47$ {$a=$quotient} if the number is divided by 19, remainder is also divided by 19.

So $\dfrac{47}{19}$ leaves a remainder of 9 (ans).