Aptitude Discussion

Q. |
Suppose n is an integer such that the sum of digits on $n$ is 2, and $10^{10} < n×10^n$. The number of different values of $n$ is: |

✖ A. |
8 |

✖ B. |
9 |

✖ C. |
10 |

✔ D. |
11 |

**Solution:**

Option(**D**) is correct

We have,

i). $10^{10} < n < 10^{11}$

ii). Sum of the digits for $'n' = 2$

Clearly, $ n_{min} = 10000000001$ (1 followed by 9 zeros and finally 1)

Obviously, we can form 10 such numbers by shifting '1' by one place from right to left again and again.

Again, there is another possibility for '$n$', $n = 20000000000$

So finally : No. of different values for $n = 10 + 1 =$ **11**

**Aditya**

*()
*

**Araceli**

*()
*

i dont know how is work so ya you can text me at aracsan@stumail.chatham.k12.nc.us

**Apoorv**

*()
*

plz correct the question...

In the given question, kindly remove that multiplication operator and in place of it add < operator.