# Moderate Number System Solved QuestionAptitude Discussion

 Q. Suppose n is an integer such that the sum of digits on $n$ is 2, and $10^{10} < n×10^n$. The number of different values of $n$ is:
 ✖ A. 8 ✖ B. 9 ✖ C. 10 ✔ D. 11

Solution:
Option(D) is correct

We have,
i). $10^{10} < n < 10^{11}$
ii). Sum of the digits for $'n' = 2$

Clearly, $n_{min} = 10000000001$ (1 followed by 9 zeros and finally 1)

Obviously, we can form 10 such numbers by shifting '1' by one place from right to left again and again.

Again, there is another possibility for '$n$', $n = 20000000000$

So finally : No. of different values for $n = 10 + 1 =$ 11

## (3) Comment(s)

()

In the given question, kindly remove that multiplication operator and in place of it add < operator.

Araceli
()

i dont know how is work so ya you can text me at aracsan@stumail.chatham.k12.nc.us

Apoorv
()

plz correct the question...