Number System
Aptitude

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Q.

Suppose n is an integer such that the sum of digits on $n$ is 2, and $10^{10} < n×10^n$. The number of different values of $n$ is:

 A.

8

 B.

9

 C.

10

 D.

11

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Solution:
Option(D) is correct

We have,
i). $10^{10} < n < 10^{11}$
ii). Sum of the digits for $'n' = 2$

Clearly, $ n_{min} = 10000000001$ (1 followed by 9 zeros and finally 1)

Obviously, we can form 10 such numbers by shifting '1' by one place from right to left again and again.

Again, there is another possibility for '$n$', $n = 20000000000$

So finally : No. of different values for $n = 10 + 1 =$ 11


(3) Comment(s)


Aditya
 ()

In the given question, kindly remove that multiplication operator and in place of it add < operator.



Araceli
 ()

i dont know how is work so ya you can text me at aracsan@stumail.chatham.k12.nc.us



Apoorv
 ()

plz correct the question... Scared Tongue