Aptitude Discussion

Q. |
If a person makes a row of toys of 20 each, there would be 15 toys left. If they made to stand in rows of 25 each, there would be 20 toys left, if they made to stand in rows of 38 each, there would be 33 toys left and if they are made to stand in rows of 40 each, there would be 35 toys left. What is the minimum number of toys the person have? |

✖ A. |
1,255 |

✖ B. |
3,805 |

✖ C. |
7,595 |

✔ D. |
3,795 |

**Solution:**

Option(**D**) is correct

Required number of toys $= LCM (20, 25, 28, 38 \text{ and } 40) – 5$

⇒ $3,800-5 =$ **3,795.**

**Arman**

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**Prabha**

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If you can see the pattern, he places 20 each row and 15 left, then places 25 each 20 left, then places 38 each row 33 left and places 40 each row 35 left. So our aim is to take LCM of 20,25,38 and 40 and have to subtract reminders with each divisors.

But instead of doing that, just subtract the common reminder which is 5 from the LCM. Case closed!!!

**Vishal Sood**

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5 is subtracted because remainer is minus 5 in each case

**AMit**

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Correction

I am not sure, why exactly 5 is subtracted. Kindly explain.

5 is subtracted because we are taking lcm of all those number which are differ by 5.

i m not sure .....using hit and trial

**AMit**

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I am sure, why exactly 5 is subtracted. Kindly explain.

Where does 28 comes from in the explanation ?