Aptitude Discussion

Q. |
2ab5 is a four-digit number divisible by 25. If the number formed from the two digits ab is a multiple of 13, then $ab =$ |

✖ A. |
10 |

✖ B. |
25 |

✔ C. |
52 |

✖ D. |
65 |

**Solution:**

Option(**C**) is correct

We have given that the number $2ab5$ is divisible by 25.

Any number divisible by 25 ends with the last two digits 00, 25, 50, or 75.

So, $b5$ should equal 25 or 75.

Hence, $b = 2$ or $7$.

Since $a$ is now free to take any digit from 0 through 9, $ab$ can have multiple values.

We also have that $ab$ is divisible by 13.

The multiples of 13 are $13, 26, 39, 52, 65, 78$ and $491$.

Among these, the only number ending with 2 or 7 is 52.

Hence, $ab=52$

**Shobia**

*()
*

from the question we can clearly understand that ab is a multiple of 13,,

so from the above 4 option 52 is only a multiple of 13.

so ans:52