Aptitude Discussion

Q. |
A milk vendor has 2 cans of milk .The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the container so as to get 12 litres of milk such that the ratio of water to milk is 3:5? |

✔ A. |
6 litres |

✖ B. |
1 litres |

✖ C. |
8 litres |

✖ D. |
7 litres |

**Solution:**

Option(**A**) is correct

Milk in 1 litre mixture in 1st can = 3/4 litre.

Milk in 1 litre mixture in 2n d can = 1/2 litre.

Milk in 1 litre final mixture = 5/8 litre.

By rule of alligation we have required ratio 5 : 8

3/4 1/2

\ /

(5/8)

/ \

1/8 : 1/8

Therefore ratio of two mixtures:

$=\dfrac{1}{8}:\dfrac{1}{8}$

$=1:1$

So, quantity of mixture taken from each can,

$=\dfrac{1}{2}\times 12$

$= 6$ litres

**Harshal**

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**Anonymous**

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Question is wrong!

The first can should contain $25\%$ water and rest milk.

1st can can not contain 75% water. Ratio of milk to total mixture must be greater than $\dfrac{5}{8}$ since other can already contains lesser ration of milk ($\dfrac{1}{2}$).

Two can of less milk can not give higher milk percentage when mixed.