# Moderate Alligations or Mixtures Solved QuestionAptitude Discussion

 Q. A milk vendor has 2 cans of milk .The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the container so as to get 12 litres of milk such that the ratio of water to milk is 3:5?
 ✔ A. 6 litres ✖ B. 1 litres ✖ C. 8 litres ✖ D. 7 litres

Solution:
Option(A) is correct

Milk in 1 litre mixture in 1st can = 3/4 litre.
Milk in 1 litre mixture in 2n d can = 1/2 litre.
Milk in 1 litre final mixture = 5/8 litre.
By rule of alligation we have required ratio 5 : 8

3/4                        1/2

\                 /
(5/8)

/                 \

1/8              :            1/8

Therefore ratio of two mixtures:
$=\dfrac{1}{8}:\dfrac{1}{8}$
$=1:1$

So, quantity of mixture taken from each can,
$=\dfrac{1}{2}\times 12$
$= 6$ litres

## (2) Comment(s)

Harshal
()

1st can can not contain 75% water. Ratio of milk to total mixture must be greater than $\dfrac{5}{8}$ since other can already contains lesser ration of milk ($\dfrac{1}{2}$).

Two can of less milk can not give higher milk percentage when mixed.

Anonymous
()

Question is wrong!

The first can should contain $25\%$ water and rest milk.